$$a^2+7 = 16$$
Answer
$$ \begin{matrix}a_1 = 3 & a_2 = -3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} a^2+7 &= 16&& \text{move all terms to the left hand side } \\[1 em]a^2+7-16 &= 0&& \text{simplify left side} \\[1 em]a^2-9 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-9 = 0 $ is a quadratic equation.
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