$$ \begin{aligned} 8+2x &= 2(x+4)&& \text{simplify left and right hand side} \\[1 em]2x+8 &= 2x+8&& \text{move the $ \color{blue}{ 2x } $ to the left side and $ \color{blue}{ 8 }$ to the right} \\[1 em]2x-2x &= 8-8&& \text{simplify left and right hand side} \\[1 em]2x-2x &= 0&& \\[1 em]0 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{blue}{ 0 = 0 } $ is TRUE for any value of $ x $, we conclude that the equation has infinitely many solutions.
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