$$\frac{81}{4}x+9\cdot0 = 0$$
Answer
$$ x = 0 $$
Explanation
$$ \begin{aligned} \frac{81}{4}x+9\cdot0 &= 0&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4 \cdot \frac{81}{4}x+4\cdot9\cdot0 &= 4\cdot0&& \text{cancel out the denominators} \\[1 em]81x+0 &= 0&& \text{ divide both sides by $ 81 $ } \\[1 em]x &= \frac{0}{81}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$
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