$$8(\frac{3}{8}x+\frac{1}{4}) = 0$$
Answer
$$ x = -\frac{2}{3} $$
Explanation
$$ \begin{aligned} 8(\frac{3}{8}x+\frac{1}{4}) &= 0&& \text{simplify left side} \\[1 em]8(\frac{3x}{8}+\frac{1}{4}) &= 0&& \\[1 em]8 \cdot \frac{3x+2}{8} &= 0&& \\[1 em]3x+2 &= 0&& \text{ move the constants to the right } \\[1 em]3x &= -2&& \text{ divide both sides by $ 3 $ } \\[1 em]x &= -\frac{2}{3}&& \\[1 em] \end{aligned} $$
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