$$8(\frac{3}{4}+x) = 0$$

$$ \begin{aligned} 8(\frac{3}{4}+x) &= 0&& \text{simplify left side} \\[1 em]8 \cdot \frac{4x+3}{4} &= 0&& \\[1 em]\frac{32x+24}{4} &= 0&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4 \cdot \frac{32x+24}{4} &= 4\cdot0&& \text{cancel out the denominators} \\[1 em]32x+24 &= 0&& \text{ move the constants to the right } \\[1 em]32x &= -24&& \text{ divide both sides by $ 32 $ } \\[1 em]x &= -\frac{24}{32}&& \\[1 em]x &= -\frac{3}{4}&& \\[1 em] \end{aligned} $$

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