$$\frac{77}{10}-\frac{3}{20}g = \frac{1}{10}g+\frac{49}{10}$$

$$ \begin{aligned} \frac{77}{10}-\frac{3}{20}g &= \frac{1}{10}g+\frac{49}{10}&& \text{multiply ALL terms by } \color{blue}{ 20 }. \\[1 em]20\cdot\frac{77}{10}-20\frac{3}{20}g &= 20 \cdot \frac{1}{10}g+20\cdot\frac{49}{10}&& \text{cancel out the denominators} \\[1 em]154-3g &= 2g+98&& \text{move the $ \color{blue}{ 2g } $ to the left side and $ \color{blue}{ 154 }$ to the right} \\[1 em]-3g-2g &= 98-154&& \text{simplify left and right hand side} \\[1 em]-5g &= -56&& \text{ divide both sides by $ -5 $ } \\[1 em]g &= \frac{-56}{-5}&& \\[1 em]g &= \frac{56}{5}&& \\[1 em] \end{aligned} $$

This page was created using