$$7(y-2) = 4y-29$$

$$ \begin{aligned} 7(y-2) &= 4y-29&& \text{simplify left side} \\[1 em]7y-14 &= 4y-29&& \text{move the $ \color{blue}{ 4y } $ to the left side and $ \color{blue}{ -14 }$ to the right} \\[1 em]7y-4y &= -29+14&& \text{simplify left and right hand side} \\[1 em]3y &= -15&& \text{ divide both sides by $ 3 $ } \\[1 em]y &= -\frac{15}{3}&& \\[1 em]y &= -5&& \\[1 em] \end{aligned} $$

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