$$ \begin{aligned} 7\cdot(2-x)+9x &= 2(x+7)&& \text{simplify left and right hand side} \\[1 em]14-7x+9x &= 2x+14&& \\[1 em]2x+14 &= 2x+14&& \text{move the $ \color{blue}{ 2x } $ to the left side and $ \color{blue}{ 14 }$ to the right} \\[1 em]2x-2x &= 14-14&& \text{simplify left and right hand side} \\[1 em]2x-2x &= 0&& \\[1 em]0 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{blue}{ 0 = 0 } $ is TRUE for any value of $ x $, we conclude that the equation has infinitely many solutions.
This page was created using
Equations Solver