$$6x(2x+3) = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = -\dfrac{ 3 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 6x(2x+3) &= 0&& \text{simplify left side} \\[1 em]12x^2+18x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 12x^{2}+18x = 0 } $, first we need to factor our $ x $.
$$ 12x^{2}+18x = x \left( 12x+18 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 12x+18 = 0$.
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