$$6+\frac{\frac{1}{1}}{3} = \frac{\frac{1}{1^2}}{3}$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 6+\frac{\frac{1}{1}}{3} &= \frac{\frac{1}{1^2}}{3}&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3\cdot6+3 \cdot \frac{\frac{1}{1}}{3} &= 3 \cdot \frac{\frac{1}{1^2}}{3}&& \text{cancel out the denominators} \\[1 em]18+1 &= 1&& \text{simplify left side} \\[1 em]19 &= 1&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 19 = 1 } $ is FALSE, we conclude that the equation has no solution.
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