$$6p-\frac{2}{p} = 0$$
Answer
$$ \begin{matrix}p_1 = - \dfrac{\sqrt{ 3 }}{ 3 } & p_2 = \dfrac{\sqrt{ 3 }}{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 6p-\frac{2}{p} &= 0&& \text{multiply ALL terms by } \color{blue}{ p }. \\[1 em]p\cdot6p-p\cdot\frac{2}{p} &= p\cdot0&& \text{cancel out the denominators} \\[1 em]6p^2-2 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}-2 = 0 $ is a quadratic equation.
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