$$ \begin{aligned} \frac{6}{x+1} &= \frac{x+2}{x+1}&& \text{multiply ALL terms by } \color{blue}{ x+1 }. \\[1 em](x+1)\cdot\frac{6}{x+1} &= (x+1)\frac{x+2}{x+1}&& \text{cancel out the denominators} \\[1 em]6 &= x+2&& \text{ swap the left and right side of the equation } \\[1 em]x+2 &= 6&& \text{ move 2 to the right } \\[1 em]x &= 6-2&& \\[1 em]x &= 4&& \\[1 em]x &= 4&& \\[1 em] \end{aligned} $$
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