$$5 \cdot \frac{x^2}{3}-7x+6 = 0$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = \dfrac{ 6 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 5 \cdot \frac{x^2}{3}-7x+6 &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3\cdot5 \cdot \frac{x^2}{3}-3\cdot7x+3\cdot6 &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]5x^2-21x+18 &= 0&& \\[1 em] \end{aligned} $$
$ 5x^{2}-21x+18 = 0 $ is a quadratic equation.
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