$$5c+\frac{38}{4}c+40-1 = 0$$

$$ \begin{aligned} 5c+\frac{38}{4}c+40-1 &= 0&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4\cdot5c+4 \cdot \frac{38}{4}c+4\cdot40-4\cdot1 &= 4\cdot0&& \text{cancel out the denominators} \\[1 em]20c+38c+160-4 &= 0&& \text{simplify left side} \\[1 em]58c+156 &= 0&& \text{ move the constants to the right } \\[1 em]58c &= -156&& \text{ divide both sides by $ 58 $ } \\[1 em]c &= -\frac{156}{58}&& \\[1 em]c &= -\frac{78}{29}&& \\[1 em] \end{aligned} $$

This page was created using