Question
$$5x\cdot15-(41-6)+2^3 = 0$$
Answer
$$ x = \dfrac{9}{25} $$
Explanation
$$ \begin{aligned} 5x\cdot15-(41-6)+2^3 &= 0&& \text{simplify left side} \\[1 em]75x-35+2^3 &= 0&& \\[1 em]75x-35+8 &= 0&& \\[1 em]75x-27 &= 0&& \text{ move the constants to the right } \\[1 em]75x &= 27&& \text{ divide both sides by $ 75 $ } \\[1 em]x &= \frac{27}{75}&& \\[1 em]x &= \frac{9}{25}&& \\[1 em] \end{aligned} $$
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