$$5+\frac{10}{2}x\cdot4-3 = 0$$

$$ \begin{aligned} 5+\frac{10}{2}x\cdot4-3 &= 0&& \text{multiply ALL terms by } \color{blue}{ 2 }. \\[1 em]2\cdot5+2 \cdot \frac{10}{2}x\cdot4-2\cdot3 &= 2\cdot0&& \text{cancel out the denominators} \\[1 em]10+40x-6 &= 0&& \text{simplify left side} \\[1 em]40x+4 &= 0&& \text{ move the constants to the right } \\[1 em]40x &= -4&& \text{ divide both sides by $ 40 $ } \\[1 em]x &= -\frac{4}{40}&& \\[1 em]x &= -\frac{1}{10}&& \\[1 em] \end{aligned} $$

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