$$ \begin{aligned} 5 &= 4a-7&& \text{ swap the left and right side of the equation } \\[1 em]4a-7 &= 5&& \text{ move -7 to the right } \\[1 em]4a &= 5+7&& \\[1 em]4a &= 12&& \text{ divide both sides by $ 4 $ } \\[1 em]a &= \frac{12}{4}&& \\[1 em]a &= 3&& \\[1 em] \end{aligned} $$