$$ \begin{aligned} 5\cdot(3-x) &= 5+5x&& \text{simplify left and right hand side} \\[1 em]15-5x &= 5x+5&& \\[1 em]-5x+15 &= 5x+5&& \text{move the $ \color{blue}{ 5x } $ to the left side and $ \color{blue}{ 15 }$ to the right} \\[1 em]-5x-5x &= 5-15&& \text{simplify left and right hand side} \\[1 em]-10x &= -10&& \text{ divide both sides by $ -10 $ } \\[1 em]x &= \frac{-10}{-10}&& \\[1 em]x &= 1&& \\[1 em] \end{aligned} $$

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