$$4k(k-6) = 0$$
Answer
$$ \begin{matrix}k_1 = 0 & k_2 = 6 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 4k(k-6) &= 0&& \text{simplify left side} \\[1 em]4k^2-24k &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 4x^{2}-24x = 0 } $, first we need to factor our $ x $.
$$ 4x^{2}-24x = x \left( 4x-24 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 4x-24 = 0$.
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