$$ \begin{aligned} \frac{4}{4+2} &= \frac{10}{15}&& \text{multiply ALL terms by } \color{blue}{ 30 }. \\[1 em]30\cdot\frac{4}{4+2} &= 30\cdot\frac{10}{15}&& \text{cancel out the denominators} \\[1 em]20 &= 20&& \\[1 em] \end{aligned} $$
Since the statement $ \color{blue}{ 20 = 20 } $ is TRUE for any value of $ x $, we conclude that the equation has infinitely many solutions.
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