$$ \begin{aligned} 4(x+1)+2(x-3) &= 3(x-2)+3(x+5)&& \text{simplify left and right hand side} \\[1 em]4x+4+2x-6 &= 3x-6+3x+15&& \\[1 em]6x-2 &= 6x+9&& \text{move the $ \color{blue}{ 6x } $ to the left side and $ \color{blue}{ -2 }$ to the right} \\[1 em]6x-6x &= 9+2&& \text{simplify left and right hand side} \\[1 em]6x-6x &= 11&& \\[1 em]0 &= 11&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 0 = 11 } $ is FALSE, we conclude that the equation has no solution.
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