$$ \begin{aligned} 4(2x+5) &= 8x+5&& \text{simplify left side} \\[1 em]8x+20 &= 8x+5&& \text{move the $ \color{blue}{ 8x } $ to the left side and $ \color{blue}{ 20 }$ to the right} \\[1 em]8x-8x &= 5-20&& \text{simplify left and right hand side} \\[1 em]8x-8x &= -15&& \\[1 em]0 &= -15&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 0 = -15 } $ is FALSE, we conclude that the equation has no solution.
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