$$3x-\frac{1}{4}x+3 = \frac{7}{5}$$

$$ \begin{aligned} 3x-\frac{1}{4}x+3 &= \frac{7}{5}&& \text{multiply ALL terms by } \color{blue}{ 20 }. \\[1 em]20\cdot3x-20 \cdot \frac{1}{4}x+20\cdot3 &= 20\cdot\frac{7}{5}&& \text{cancel out the denominators} \\[1 em]60x-5x+60 &= 28&& \text{simplify left side} \\[1 em]55x+60 &= 28&& \text{ move 60 to the right } \\[1 em]55x &= 28-60&& \\[1 em]55x &= -32&& \text{ divide both sides by $ 55 $ } \\[1 em]x &= -\frac{32}{55}&& \\[1 em] \end{aligned} $$

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