$$3x-(2x-5)(x+2) = 0$$
Answer
$$ \begin{matrix}x_1 = 1-\sqrt{ 6 } & x_2 = 1+\sqrt{ 6 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3x-(2x-5)(x+2) &= 0&& \text{simplify left side} \\[1 em]3x-(2x^2+4x-5x-10) &= 0&& \\[1 em]3x-(2x^2-x-10) &= 0&& \\[1 em]3x-2x^2+x+10 &= 0&& \\[1 em]-2x^2+4x+10 &= 0&& \\[1 em] \end{aligned} $$
$ -2x^{2}+4x+10 = 0 $ is a quadratic equation.
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