$3 x - (2 x - 5) (x + 2) = 0$

Answer

$x_{1} = 1 - 6 x_{2} = 1 + 6$

Explanation

3 x - (2 x - 5) (x + 2) 3 x - (2 x^{2} + 4 x - 5 x - 10) 3 x - (2 x^{2} - x - 10) 3 x - 2 x^{2} + x + 10 - 2 x^{2} + 4 x + 10 = 0 = 0 = 0 = 0 = 0 simplify left side

$- 2 x^{2} + 4 x + 10 = 0$ is a quadratic equation.

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.

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3x−(2x−5)(x+2)=0

x1​=1−6​​x2​=1+6​​

$3 x - (2 x - 5) (x + 2) = 0$

$x_{1} = 1 - 6 x_{2} = 1 + 6$