$$3x^2-7x+8 = 14$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 2 }{ 3 } & x_2 = 3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3x^2-7x+8 &= 14&& \text{move all terms to the left hand side } \\[1 em]3x^2-7x+8-14 &= 0&& \text{simplify left side} \\[1 em]3x^2-7x-6 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-7x-6 = 0 $ is a quadratic equation.
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