$$3x(4x-6) = 2\cdot3x$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = 2 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3x(4x-6) &= 2\cdot3x&& \text{simplify left and right hand side} \\[1 em]12x^2-18x &= 6x&& \text{move all terms to the left hand side } \\[1 em]12x^2-18x-6x &= 0&& \text{simplify left side} \\[1 em]12x^2-24x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 12x^{2}-24x = 0 } $, first we need to factor our $ x $.
$$ 12x^{2}-24x = x \left( 12x-24 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 12x-24 = 0$.
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