$$\frac{33}{10}x+\frac{4}{1} = 16-\frac{15}{10}x$$

$$ \begin{aligned} \frac{33}{10}x+\frac{4}{1} &= 16-\frac{15}{10}x&& \text{multiply ALL terms by } \color{blue}{ 10 }. \\[1 em]10 \cdot \frac{33}{10}x+10\cdot\frac{4}{1} &= 10\cdot16-10 \cdot \frac{15}{10}x&& \text{cancel out the denominators} \\[1 em]33x+40 &= 160-15x&& \text{move the $ \color{blue}{ -15x } $ to the left side and $ \color{blue}{ 40 }$ to the right} \\[1 em]33x+15x &= 160-40&& \text{simplify left and right hand side} \\[1 em]48x &= 120&& \text{ divide both sides by $ 48 $ } \\[1 em]x &= \frac{120}{48}&& \\[1 em]x &= \frac{5}{2}&& \\[1 em] \end{aligned} $$

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