$$3 = (x+1)(3x-6)$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 13 }}{ 2 } & x_2 = \dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 13 }}{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3 &= (x+1)(3x-6)&& \text{simplify right side} \\[1 em]3 &= 3x^2-6x+3x-6&& \\[1 em]3 &= 3x^2-3x-6&& \text{move all terms to the left hand side } \\[1 em]3-3x^2+3x+6 &= 0&& \text{simplify left side} \\[1 em]-3x^2+3x+9 &= 0&& \\[1 em] \end{aligned} $$
$ -3x^{2}+3x+9 = 0 $ is a quadratic equation.
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