$$\frac{3}{9} = \frac{3}{x}+2$$

$$ \begin{aligned} \frac{3}{9} &= \frac{3}{x}+2&& \text{multiply ALL terms by } \color{blue}{ 9x }. \\[1 em]9x\cdot\frac{3}{9} &= 9x\cdot\frac{3}{x}+9x\cdot2&& \text{cancel out the denominators} \\[1 em]3x &= 27+18x&& \text{move the $ \color{blue}{ 18x } $ to the left side} \\[1 em]3x-18x &= 27&& \text{simplify left side} \\[1 em]-15x &= 27&& \text{ divide both sides by $ -15 $ } \\[1 em]x &= -\frac{27}{15}&& \\[1 em]x &= -\frac{9}{5}&& \\[1 em] \end{aligned} $$

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