$$ \begin{aligned} 3(x+7)+6(3x+4) &= 0&& \text{simplify left side} \\[1 em]3x+21+18x+24 &= 0&& \\[1 em]21x+45 &= 0&& \text{ move the constants to the right } \\[1 em]21x &= -45&& \text{ divide both sides by $ 21 $ } \\[1 em]x &= -\frac{45}{21}&& \\[1 em]x &= -\frac{15}{7}&& \\[1 em] \end{aligned} $$
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