$$3(x+4)(x-3) = 0$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = -4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 3(x+4)(x-3) &= 0&& \text{simplify left side} \\[1 em](3x+12)(x-3) &= 0&& \\[1 em]3x^2-9x+12x-36 &= 0&& \\[1 em]3x^2+3x-36 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+3x-36 = 0 $ is a quadratic equation.
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