$$3(8x\cdot2+2x-4) = 0$$
Answer
$$ x = \frac{2}{9} $$
Explanation
$$ \begin{aligned} 3(8x\cdot2+2x-4) &= 0&& \text{simplify left side} \\[1 em]3(16x+2x-4) &= 0&& \\[1 em]3(18x-4) &= 0&& \\[1 em]54x-12 &= 0&& \text{ move the constants to the right } \\[1 em]54x &= 12&& \text{ divide both sides by $ 54 $ } \\[1 em]x &= \frac{12}{54}&& \\[1 em]x &= \frac{2}{9}&& \\[1 em] \end{aligned} $$
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