$$ \begin{aligned} 2x-8 &= 2(x-1)&& \text{simplify right side} \\[1 em]2x-8 &= 2x-2&& \text{move the $ \color{blue}{ 2x } $ to the left side and $ \color{blue}{ -8 }$ to the right} \\[1 em]2x-2x &= -2+8&& \text{simplify left and right hand side} \\[1 em]2x-2x &= 6&& \\[1 em]0 &= 6&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 0 = 6 } $ is FALSE, we conclude that the equation has no solution.
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