$$ \begin{aligned} 2x-\frac{3}{9}x &= \frac{8}{15}&& \text{multiply ALL terms by } \color{blue}{ 45 }. \\[1 em]45\cdot2x-45 \cdot \frac{3}{9}x &= 45\cdot\frac{8}{15}&& \text{cancel out the denominators} \\[1 em]90x-15x &= 24&& \text{simplify left side} \\[1 em]75x &= 24&& \text{ divide both sides by $ 75 $ } \\[1 em]x &= \frac{24}{75}&& \\[1 em]x &= \frac{8}{25}&& \\[1 em] \end{aligned} $$
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