$$2x-\frac{1}{12}-x-\frac{1}{33}x+\frac{1}{4} = 0$$

$$ \begin{aligned} 2x-\frac{1}{12}-x-\frac{1}{33}x+\frac{1}{4} &= 0&& \text{multiply ALL terms by } \color{blue}{ 132 }. \\[1 em]132\cdot2x-132\cdot\frac{1}{12}-132x-132\frac{1}{33}x+132\cdot\frac{1}{4} &= 132\cdot0&& \text{cancel out the denominators} \\[1 em]264x-11-132x-4x+33 &= 0&& \text{simplify left side} \\[1 em]128x+22 &= 0&& \text{ move the constants to the right } \\[1 em]128x &= -22&& \text{ divide both sides by $ 128 $ } \\[1 em]x &= -\frac{22}{128}&& \\[1 em]x &= -\frac{11}{64}&& \\[1 em] \end{aligned} $$

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