$$2x^2-3x-1 = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 3 }{ 4 }-\dfrac{\sqrt{ 17 }}{ 4 } & x_2 = \dfrac{ 3 }{ 4 }+\dfrac{\sqrt{ 17 }}{ 4 } \\[1 em] \end{matrix} $$
Explanation
$ 2x^{2}-3x-1 = 0 $ is a quadratic equation.
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