$$2 \cdot \frac{x}{x+1} = 0$$
Answer
$$ x = 0 $$
Explanation
$$ \begin{aligned} 2 \cdot \frac{x}{x+1} &= 0&& \text{multiply ALL terms by } \color{blue}{ x+1 }. \\[1 em](x+1)\cdot2 \cdot \frac{x}{x+1} &= (x+1)\cdot0&& \text{cancel out the denominators} \\[1 em]2x &= 0&& \text{ divide both sides by $ 2 $ } \\[1 em]x &= \frac{0}{2}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$
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