$$2x(5x-5) = 2x$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = \dfrac{ 6 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2x(5x-5) &= 2x&& \text{simplify left side} \\[1 em]10x^2-10x &= 2x&& \text{move all terms to the left hand side } \\[1 em]10x^2-10x-2x &= 0&& \text{simplify left side} \\[1 em]10x^2-12x &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 10x^{2}-12x = 0 } $, first we need to factor our $ x $.
$$ 10x^{2}-12x = x \left( 10x-12 \right) $$$ x = 0 $ is a root of multiplicity $ 1 $.
The second root can be found by solving equation $ 10x-12 = 0$.
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