$$ \begin{aligned} 2 &= x(5-1)^2+2&& \text{simplify right side} \\[1 em]2 &= x\cdot4^2+2&& \\[1 em]2 &= x\cdot16+2&& \text{ swap the left and right side of the equation } \\[1 em]x\cdot16+2 &= 2&& \text{ move 2 to the right } \\[1 em]16x &= 2-2&& \\[1 em]16x &= 0&& \text{ divide both sides by $ 16 $ } \\[1 em]x &= \frac{0}{16}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$
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