Question
$$2^2(x+3)+9-5 = 0$$
Answer
$$ x = -4 $$
Explanation
$$ \begin{aligned} 2^2(x+3)+9-5 &= 0&& \text{simplify left side} \\[1 em]4(x+3)+9-5 &= 0&& \\[1 em]4x+12+9-5 &= 0&& \\[1 em]4x+16 &= 0&& \text{ move the constants to the right } \\[1 em]4x &= -16&& \text{ divide both sides by $ 4 $ } \\[1 em]x &= -\frac{16}{4}&& \\[1 em]x &= -4&& \\[1 em] \end{aligned} $$
This page was created using
Equations Solver