$$\frac{2}{6}+\frac{1}{2x} = \frac{1}{3}$$

$$ \begin{aligned} \frac{2}{6}+\frac{1}{2x} &= \frac{1}{3}&& \text{multiply ALL terms by } \color{blue}{ 6\cdot2x\cdot3 }. \\[1 em]6\cdot2x\cdot3\cdot\frac{2}{6}+6\cdot2x\cdot3\cdot\frac{1}{2x} &= 6\cdot2x\cdot3\cdot\frac{1}{3}&& \text{cancel out the denominators} \\[1 em]12x+18x^2 &= 12x&& \text{simplify left side} \\[1 em]18x^2+12x &= 12x&& \text{move all terms to the left hand side } \\[1 em]18x^2+12x-12x &= 0&& \text{simplify left side} \\[1 em]18x^2+12x-12x &= 0&& \\[1 em]18x^2 &= 0&& \\[1 em] \end{aligned} $$

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