$$ \begin{aligned} \frac{2}{49}+\frac{2}{49}+\frac{2}{49}+\frac{2}{49}+\frac{2}{49}+\frac{2}{49} &= 0&& \text{multiply ALL terms by } \color{blue}{ 49 }. \\[1 em]49\cdot\frac{2}{49}+49\cdot\frac{2}{49}+49\cdot\frac{2}{49}+49\cdot\frac{2}{49}+49\cdot\frac{2}{49}+49\cdot\frac{2}{49} &= 49\cdot0&& \text{cancel out the denominators} \\[1 em]2+2+2+2+2+2 &= 0&& \text{simplify left side} \\[1 em]12 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 12 = 0 } $ is FALSE, we conclude that the equation has no solution.
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