$$2(x+1)^2+2(x+1)-40 = 0$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = -6 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2(x+1)^2+2(x+1)-40 &= 0&& \text{simplify left side} \\[1 em]2(x^2+2x+1)+2(x+1)-40 &= 0&& \\[1 em]2x^2+4x+2+2x+2-40 &= 0&& \\[1 em]2x^2+6x+4-40 &= 0&& \\[1 em]2x^2+6x-36 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}+6x-36 = 0 $ is a quadratic equation.
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