$$2(9x^2+6x+1) = (3x+1)(x-2)$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 3 } & x_2 = -\dfrac{ 4 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2(9x^2+6x+1) &= (3x+1)(x-2)&& \text{simplify left and right hand side} \\[1 em]18x^2+12x+2 &= 3x^2-6x+x-2&& \\[1 em]18x^2+12x+2 &= 3x^2-5x-2&& \text{move all terms to the left hand side } \\[1 em]18x^2+12x+2-3x^2+5x+2 &= 0&& \text{simplify left side} \\[1 em]15x^2+17x+4 &= 0&& \\[1 em] \end{aligned} $$
$ 15x^{2}+17x+4 = 0 $ is a quadratic equation.
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