$$ \begin{aligned} 2(5x-2) &= 10x+4&& \text{simplify left side} \\[1 em]10x-4 &= 10x+4&& \text{move the $ \color{blue}{ 10x } $ to the left side and $ \color{blue}{ -4 }$ to the right} \\[1 em]10x-10x &= 4+4&& \text{simplify left and right hand side} \\[1 em]10x-10x &= 8&& \\[1 em]0 &= 8&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 0 = 8 } $ is FALSE, we conclude that the equation has no solution.
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