$$2\cdot(3+3x) = -2x+38$$

$$ \begin{aligned} 2\cdot(3+3x) &= -2x+38&& \text{simplify left side} \\[1 em]6+6x &= -2x+38&& \\[1 em]6x+6 &= -2x+38&& \text{move the $ \color{blue}{ -2x } $ to the left side and $ \color{blue}{ 6 }$ to the right} \\[1 em]6x+2x &= 38-6&& \text{simplify left and right hand side} \\[1 em]8x &= 32&& \text{ divide both sides by $ 8 $ } \\[1 em]x &= \frac{32}{8}&& \\[1 em]x &= 4&& \\[1 em] \end{aligned} $$

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