$$2\cdot3-2\cdot4x+7 = 0$$
Answer
$$ x = \frac{13}{8} $$
Explanation
$$ \begin{aligned} 2\cdot3-2\cdot4x+7 &= 0&& \text{simplify left side} \\[1 em]6-2\cdot4x+7 &= 0&& \\[1 em]6-8x+7 &= 0&& \\[1 em]-8x+13 &= 0&& \text{ move the constants to the right } \\[1 em]-8x &= -13&& \text{ divide both sides by $ -8 $ } \\[1 em]x &= \frac{-13}{-8}&& \\[1 em]x &= \frac{13}{8}&& \\[1 em] \end{aligned} $$
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