$$2(2x^4-7x^2+6) = 0$$
Answer
$$ \begin{matrix}x_1 = 1.22474 & x_2 = -1.22474 & x_3 = 1.41421 \\[1 em] x_4 = -1.41421 & \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 2(2x^4-7x^2+6) &= 0&& \text{simplify left side} \\[1 em]4x^4-14x^2+12 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using quartic formulas
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