$$2\cdot(1-x) = 5\cdot(1+2x)+5$$

$$ \begin{aligned} 2\cdot(1-x) &= 5\cdot(1+2x)+5&& \text{simplify left and right hand side} \\[1 em]2-2x &= 5+10x+5&& \\[1 em]-2x+2 &= 10x+10&& \text{move the $ \color{blue}{ 10x } $ to the left side and $ \color{blue}{ 2 }$ to the right} \\[1 em]-2x-10x &= 10-2&& \text{simplify left and right hand side} \\[1 em]-12x &= 8&& \text{ divide both sides by $ -12 $ } \\[1 em]x &= -\frac{8}{12}&& \\[1 em]x &= -\frac{2}{3}&& \\[1 em] \end{aligned} $$

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