$$16x^2 = 121$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 11 }{ 4 } & x_2 = -\dfrac{ 11 }{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 16x^2 &= 121&& \text{move all terms to the left hand side } \\[1 em]16x^2-121 &= 0&& \\[1 em] \end{aligned} $$
$ 16x^{2}-121 = 0 $ is a quadratic equation.
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